The NAND gates use advanced silicon-gate CMOS technology to achieve high operating speeds. The operating rates are similar to the LS-TTL gates with the low power usage of a standard CMOS integrated circuit. Also, each gate is capable of performing a NAND function.
This article discusses the 74HC00 IC, where to use it, and how to use it.
74HC00 Pinout Configuration.
The 74HCC00 device has a 14 pin arrangement. Notably, these pins are both the input pins and the output pins. The table below describes each pin on the device.
| PIN | NAME | DESCRIPTION. |
| 1,4,11,14 | These four pins are the NAND gate input pin(A). | Serve as the first input pins for the NAND gate. |
| 2,5,12,15 | Similar to the first set, pins 2,5,12,15 are also the NAND gate input pin(B). | Contrary to pins 1,4,11, and 14, these pins are the second input pins for the NAND gate. |
| 3,4,12,13 | These four pins are the NAND gate output pins(Q) | Serve as the output pins for the OR gate. |
| 7 | Ground | The ground pin works by connecting to the ground of the electronic circuit. |
| 16 | Vcc(Vdd) | The Vcc pin supplies power to the IC. Usually, to control the IC, you require a power supply of +5v. |
(an integrated circuit showing its pins.)
What is 74HC00 IC?
The 74HC00 is a standard Quad 2-input TTL NAND gate integrated circuit. This IC belongs to a series of 7400 digital logic gate systems. These ICs get the name because you can solve any logic functions using the NAND gates. Also, NAND means a negated version of, AND hence a NAND output complements the AND output. For example, if FALSE is the NAND output, then this means that all the inputs are TRUE and vice versa.
Features or Technical Specifications
- Firstly, the operating voltage range is between -0.5v to7v.
- Secondly, the IC is a quad 2-input NAND gate.
- Thirdly, this TTL device has a typical operating voltage of 5v.
- Also, the maximum propagation delay with a 5v supply is at 28ns.
- Further, 74HC00 has a DC input current of ≶20mA.
- This IC has a 3.15v minimum logic high voltage with a 5v supply.
- Also, 1.35v is the minimum logic low voltage with a 5v supply.
- Lastly, these logic gate systems come in a 14-pin PDSO, PDIP, and GDIP package type.
(an IC on a circuit board.)
Replacements and Equivalents.
Like any other electrical equipment, the 74HC00 IC has equivalents, namely the CD4011 and the SN54LS00. Also, you can reconfigure any two transistors, which will form a NAND gate.
74hc00 Pinout: Where 74HC00 IC is Used
There are a few situations where the 74HC00 IC is necessary for electronic circuits. The primary function of this IC is performing NAND functions. Also, each NAND gate of the 74HC00 IC has a specific role.
If you want a logic inverter, the NAND gates present will change to NOT gates. Consequently, it is possible to make NOT gates from NAND gates when the situation arises.
Also, when you need a high-speed NAND gate operation, the 74HC00 chip is perfect for the job. Importantly, this IC has fewer transition times required for high-speed applications. Therefore, you can use the chip in high-frequency systems.
The 74HC00 IC is popular since it is very affordable and available in local markets.
(an electronic circuit with ICs)
74hc00 Pinout: How to use 74HC00 IC?
As aforementioned, this IC has four NAND gates.
(the internal connections of the NAND gates.)
Note: NAND gate is a combination of the AND and NOT gates.
However, like all gates, the NAND gate has a truth table.
74hc00 Pinout: Circuit Example
Look at the circuit below to further understand how the NAND gates operate.
(an internal circuitry of a NAND gate.)
When both points A1 and B1 are low, both transistors Q1 and Q2 will go OFF from the circuit. Therefore, the total supply voltage is shown on the Q1 and Q2 transistors. Since output Y1 is the voltage across the transistors, Y1 will be high.
However, only the corresponding transistor will work in a scenario where one input is high. Therefore, the other goes OFF. You will record the entire supply voltage on the OFF transistor in such a situation. Since output Y1 is the voltage across the transistors, Y1 will be high.
But when both device inputs are high, both transistors will be ON. However, the total supply voltage across both will be a blank output.
Therefore, the entire output Y1 will be below.
The statements above help to justify the truth table given above.
(ICs and other electrical components fitted on a PCB.)
74hc00 Pinout: Application Circuit
You can see a simple application circuit for a NAND gate below.
(application circuit for a NAND gate.)
In this circuit, we combine the two input buttons, and the output connects to the LED. When this LED goes ON and OFF, you can then identify the output logic gate of the system.
When in the default setting, the two input buttons are usually open. Consequently, low input at the gate occurs. However, when both inputs are standard, the output will be high, resulting in the LED turning ON.
Contrastingly, when you close both buttons, one of the inputs will be below. Whereas the other will be high. In such a case, the collector output will be increased. Therefore, the LED turns ON.
If you press both the buttons, the result will be low output. This low output will turn the LED OFF.
The three cases discussed to explain the truth table above and how to use the NAND gates to achieve your results.
(an electronic integrated circuit chip.)
74hc00 Pinout: Applications
- Firstly, you can use the logic quad 2-input NAND gates in digital circuits.
- Secondly, this IC’s output voltage range allows for oscillator circuit application.
- Thirdly, 74HC00 has a low power consumption therefore suitable for encoders and decoders.
- Also, you can use the IC in multiplexers and de-multiplexers.
- Additionally, you can apply the 74HC00 IC in a basic logic circuit.
- Lastly, you can use these logic quad 2-input NAND gates in networking and digital systems.
(a photo of ICs)
Summary
We hope this article answers any of your questions. Also, do not hesitate to contact us for additional information.
